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x^2-2x=5000
We move all terms to the left:
x^2-2x-(5000)=0
a = 1; b = -2; c = -5000;
Δ = b2-4ac
Δ = -22-4·1·(-5000)
Δ = 20004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20004}=\sqrt{4*5001}=\sqrt{4}*\sqrt{5001}=2\sqrt{5001}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{5001}}{2*1}=\frac{2-2\sqrt{5001}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{5001}}{2*1}=\frac{2+2\sqrt{5001}}{2} $
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